Step 1: Recall the formula for the radius of a charged particle moving in a magnetic field:
When a charged particle with mass \(m\), charge \(q\), and velocity \(v\) enters a uniform magnetic field \(B\) perpendicular to the velocity, the radius (\(r\)) of its circular path is given by:
\[ r = \frac{mv}{qB} \]
Step 2: Define parameters clearly:
We have two particles:
Given: Both have the same velocity \(v\).
Step 3: Calculate radii separately:
- Radius for proton (\(r_p\)): \[ r_p = \frac{m_p v}{e B} \]
- Radius for alpha particle (\(r_\alpha\)): \[ r_\alpha = \frac{4 m_p v}{2 e B} = \frac{2 m_p v}{e B} \]
Step 4: Compute the ratio of radii:
\[ \frac{r_p}{r_\alpha} = \frac{\frac{m_p v}{e B}}{\frac{2 m_p v}{e B}} = \frac{1}{2} \]
Thus, the ratio of radii (proton : alpha-particle) is 1 : 2.
The magnetic force on a charged particle moving perpendicular to a magnetic field provides the centripetal force for the circular motion. The radius \( r \) of the circular path is given by the equation: \[ r = \frac{mv}{qB} \] where:
\( m \) is the mass of the particle,
\( v \) is the velocity of the particle,
\( q \) is the charge of the particle,
\( B \) is the magnetic field strength.
For a proton, the charge is \( +e \) and mass is \( m_p \). For an alpha particle (which consists of 2 protons and 2 neutrons), the charge is \( +2e \) and mass is approximately \( 4m_p \). The ratio of radii \( r_p \) for a proton and \( r_{\alpha} \) for an alpha particle is: \[ \frac{r_{\alpha}}{r_p} = \frac{m_{\alpha} q_p}{m_p q_{\alpha}} = \frac{4m_p \cdot e}{m_p \cdot 2e} = 2 \] Thus, the ratio of the radii of the proton to the alpha particle is \( 1 : 2 \).
Two long parallel wires X and Y, separated by a distance of 6 cm, carry currents of 5 A and 4 A, respectively, in opposite directions as shown in the figure. Magnitude of the resultant magnetic field at point P at a distance of 4 cm from wire Y is \( 3 \times 10^{-5} \) T. The value of \( x \), which represents the distance of point P from wire X, is ______ cm. (Take permeability of free space as \( \mu_0 = 4\pi \times 10^{-7} \) SI units.) 
A particle of charge $ q $, mass $ m $, and kinetic energy $ E $ enters in a magnetic field perpendicular to its velocity and undergoes a circular arc of radius $ r $. Which of the following curves represents the variation of $ r $ with $ E $?
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R.
Assertion A : If oxygen ion (O\(^{-2}\)) and Hydrogen ion (H\(^{+}\)) enter normal to the magnetic field with equal momentum, then the path of O\(^{-2}\) ion has a smaller curvature than that of H\(^{+}\).
Reason R : A proton with same linear momentum as an electron will form a path of smaller radius of curvature on entering a uniform magnetic field perpendicularly.
In the light of the above statements, choose the correct answer from the options given below
Match List-I with List-II and select the correct option: 