Step 1: Recall the formula for the radius of a charged particle moving in a magnetic field:
When a charged particle with mass \(m\), charge \(q\), and velocity \(v\) enters a uniform magnetic field \(B\) perpendicular to the velocity, the radius (\(r\)) of its circular path is given by:
\[ r = \frac{mv}{qB} \]
Step 2: Define parameters clearly:
We have two particles:
Given: Both have the same velocity \(v\).
Step 3: Calculate radii separately:
- Radius for proton (\(r_p\)): \[ r_p = \frac{m_p v}{e B} \]
- Radius for alpha particle (\(r_\alpha\)): \[ r_\alpha = \frac{4 m_p v}{2 e B} = \frac{2 m_p v}{e B} \]
Step 4: Compute the ratio of radii:
\[ \frac{r_p}{r_\alpha} = \frac{\frac{m_p v}{e B}}{\frac{2 m_p v}{e B}} = \frac{1}{2} \]
Thus, the ratio of radii (proton : alpha-particle) is 1 : 2.
The magnetic force on a charged particle moving perpendicular to a magnetic field provides the centripetal force for the circular motion. The radius \( r \) of the circular path is given by the equation: \[ r = \frac{mv}{qB} \] where:
\( m \) is the mass of the particle,
\( v \) is the velocity of the particle,
\( q \) is the charge of the particle,
\( B \) is the magnetic field strength.
For a proton, the charge is \( +e \) and mass is \( m_p \). For an alpha particle (which consists of 2 protons and 2 neutrons), the charge is \( +2e \) and mass is approximately \( 4m_p \). The ratio of radii \( r_p \) for a proton and \( r_{\alpha} \) for an alpha particle is: \[ \frac{r_{\alpha}}{r_p} = \frac{m_{\alpha} q_p}{m_p q_{\alpha}} = \frac{4m_p \cdot e}{m_p \cdot 2e} = 2 \] Thus, the ratio of the radii of the proton to the alpha particle is \( 1 : 2 \).
A current-carrying coil is placed in an external uniform magnetic field. The coil is free to turn in the magnetic field. What is the net force acting on the coil? Obtain the orientation of the coil in stable equilibrium. Show that in this orientation the flux of the total field (field produced by the loop + external field) through the coil is maximum.