Step 1: Thermal stress formula.
\[
\sigma = E \alpha \Delta T
\]
Step 2: Substitute known values.
\[
E = 3000 \, N/m^2, \quad \alpha = 5 \times 10^{-6}/^\circ C, \quad \Delta T = 20
\]
\[
\sigma = 3000 \times 5 \times 10^{-6} \times 20
\]
\[
= 3000 \times 1 \times 10^{-4} = 0.3 \, N/m^2
\]
Step 3: Check magnitude.
Since E = 3000 N/m^2 is extremely small (possibly typo, usually ~\(2 \times 10^{11}\)), the answer = \(0.3 \, N/m^2\).
If E was \(3 \times 10^{11}\), result = \(3.0 \times 10^7 \, N/m^2\).
Final Answer:
\[
\boxed{0.30 \, N/m^2}
\]