Question

A population of 1000 plants are in Hardy-Weinberg equilibrium. Two alleles R and r determine a particular trait in this population. If the number of plants with RR genotype is 640, Rr genotype is 320 and rr genotype is 40, the frequency of r allele (in percentage) in this population is __________/ (rounded off to the nearest integer).

Answer 1

Correct Answer: 20

The frequencies of the genotypes are:

Frequency of RR = \(\frac{640}{1000} = 0.64\),

Frequency of Rr = \(\frac{320}{1000} = 0.32\),

Frequency of rr = \(\frac{40}{1000} = 0.04\).

The frequency of the r allele (q) can be calculated using the formula:

\( q^2 = \text{frequency of rr} = 0.04, \)

\( q = \sqrt{0.04} = 0.2. \)

Thus, the frequency of the r allele is 20%.