A point P consider at contact point of a wheel on ground which rolls on ground without slipping then value of displacement of point P when wheel completes half of rotation (If radius of wheel is 1m) :
2m
\(\sqrt{\pi^2+4}\) m
\(\pi\) m
\(\sqrt{π^2+2}\) m
The correct option is (B) : \(\sqrt{\pi^2+4}\) m
displacement PQ = \(\sqrt{PM^2}\)+(QM)2=\(\sqrt {\pi R^2 +(2R)^2}\) =\(\sqrt{\pi^2+4}\) (∵ R = 1m)
A wheel of radius $ 0.2 \, \text{m} $ rotates freely about its center when a string that is wrapped over its rim is pulled by a force of $ 10 \, \text{N} $. The established torque produces an angular acceleration of $ 2 \, \text{rad/s}^2 $. Moment of inertia of the wheel is............. kg m².
Rotational motion can be defined as the motion of an object around a circular path, in a fixed orbit.
The wheel or rotor of a motor, which appears in rotation motion problems, is a common example of the rotational motion of a rigid body.
Other examples: