Let the actual length of bacteria be x cm and the enlarged length of bacteria be y cm, if the photograph is enlarged for 20,000 times.
The given information in the form of a table is as follows.
Length of bacteria (in cm) | 5 | x | y |
---|---|---|---|
Number of times photograph of Bacteria was enlarged | 50000 | 1 | 20000 |
The number of times the photograph of bacteria was enlarged, and the length of bacteria are in direct proportion.
Therefore, we obtain.
\(\frac{5}{50000}=\frac{x}{1}\)
\(⇒ x=\frac{1}{0000} =10^{-4}\)
Let the length of bacteria when the photograph of bacteria is enlarged 20, 000 times be y.
\(\frac{5}{50000}=\frac{y}{20000}\)
\(⇒ y =\frac{5×20000}{50000}=2 cm\)
Hence, the enlarged length of bacteria is 2 cm.