For distant vision = −0.181 m, for near vision = 0.667 m
The power P of a lens of focal length f is given by the relation.
\(\text{Power (P)} = \frac{1}{f}\)
(i) Power of the lens used for correcting distant vision = −5.5 D
Focal length of the required lens, \(f =\frac{1}{\text{P}}\)
\(f = \frac{1}{-5.5}\)
f = -0.181 m
The focal length of the lens for correcting distant vision is −0.181 m.
(ii) Power of the lens used for correcting near vision = +1.5 D
Focal length of the required lens, \(f =\frac{1}{\text{P}}\)
\(f = \frac{1}{1.5}\) = +0.667 m
The focal length of the lens for correcting near vision is 0.667 m.