For distant vision = −0.181 m, for near vision = 0.667 m
The power P of a lens of focal length f is given by the relation.
\(\text{Power (P)} = \frac{1}{f}\)
(i) Power of the lens used for correcting distant vision = −5.5 D
Focal length of the required lens, \(f =\frac{1}{\text{P}}\)
\(f = \frac{1}{-5.5}\)
f = -0.181 m
The focal length of the lens for correcting distant vision is −0.181 m.
(ii) Power of the lens used for correcting near vision = +1.5 D
Focal length of the required lens, \(f =\frac{1}{\text{P}}\)
\(f = \frac{1}{1.5}\) = +0.667 m
The focal length of the lens for correcting near vision is 0.667 m.

Leaves of the sensitive plant move very quickly in response to ‘touch’. How is this stimulus of touch communicated and explain how the movement takes place?
Read the following sources of loan carefully and choose the correct option related to formal sources of credit:
(i) Commercial Bank
(ii) Landlords
(iii) Government
(iv) Money Lende