Question:
A person climbs up a stalled escalator in $60\, s$ . If standing on the same but escalator running with constant velocity he takes $40\, s$. How much time is taken by the person to walk up the moving escalator ?
A person climbs up a stalled escalator in $60\, s$ . If standing on the same but escalator running with constant velocity he takes $40\, s$. How much time is taken by the person to walk up the moving escalator ?
Updated On: Apr 28, 2025
- 37 s
- 27 s
- 24 s
- 45 s
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The Correct Option is C
Solution and Explanation
$60=\frac{d}{v_{\text{man}}}$
$40=\frac{d}{v_{e s}}$
$t=\frac{d}{v_{\text{man}}+v_{e s}}$
$\frac{1}{t}=\frac{v_{\text{man}}}{d}+\frac{v_{e s}}{d}=\frac{1}{60}+\frac{1}{40}$
$t=24 \sec$
$40=\frac{d}{v_{e s}}$
$t=\frac{d}{v_{\text{man}}+v_{e s}}$
$\frac{1}{t}=\frac{v_{\text{man}}}{d}+\frac{v_{e s}}{d}=\frac{1}{60}+\frac{1}{40}$
$t=24 \sec$
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Concepts Used:
Motion in a straight line
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Types of Linear Motion:
Linear motion is also known as the Rectilinear Motion which are of two types:
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