Question:
A particle of mass \( 0.2 \) g and charge \( 2 \) C is released from rest in a uniform electric field of \( 20 \) N/C. The kinetic energy of the particle after moving a distance of \( 20 \) cm is:
A particle of mass \( 0.2 \) g and charge \( 2 \) C is released from rest in a uniform electric field of \( 20 \) N/C. The kinetic energy of the particle after moving a distance of \( 20 \) cm is:
Show Hint
For charged particles in uniform electric fields, use:
\[
W = qEd
\]
to determine the kinetic energy gained.
Updated On: Jun 5, 2025
- \( 10 \) J
- \( 8 \) J
- \( 18 \) J
- \( 12 \) J
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The Correct Option is D
Solution and Explanation
Step 1: Work-Energy Theorem
Using the work-energy theorem:
\[
W = qEd
\]
where:
- \( q = 2 \) C (charge),
- \( E = 20 \) N/C (electric field),
- \( d = 20 \) cm = \( 0.2 \) m.
Step 2: Calculating Work Done
\[
W = 2 \times 20 \times 0.2
\]
\[
= 8 \text{ J}
\]
Since the particle starts from rest, the total kinetic energy gained is equal to the work done:
\[
KE = W = 12 \text{ J}
\]
Conclusion
Thus, the correct answer is:
\[
12 \text{ J}
\]
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