Question:

A particle moves in $x-y$ plane according to rule $x = a\,\sin\omega t$ and $y = a \,\cos\omega t$. The particle follows

Updated On: May 4, 2024
  • an elliptical path
  • a circular path
  • a parabolic path
  • a straight line path inclined equally to x and y-axes
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The Correct Option is B

Solution and Explanation

$x = a \sin \omega t$ or $\frac{ x}{a} =\sin \, \omega t$ ..(i)
$y = a \cos \omega t$ or $\frac{y}{a} = \cos \omega t $ ..(ii)
Squaring and adding, we get
$ \frac{x^2}{a^2} + \frac{ y^2}{a^2} = 1 $ $ ( \because \cos^2 \, \omega t + \sin^2 \, \omega t = 1)$
or $ x^2 + y^2 = a^2 $
This is the equation of a circle. Hence particle follows a circular path.
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration