\(\frac{S}{4},\sqrt{\frac{3gS}{2}}\)
\(\frac{S}{4},{\frac{3gS}{2}}\)
\(\frac{S}{4},{\frac{\sqrt{3gS}}{2}}\)
\(\frac{S}{2},{\frac{\sqrt{3gS}}{2}}\)
The correct answer is option (A): \(\frac{S}{4},\sqrt{\frac{3gS}{2}}\)
AB is a part of an electrical circuit (see figure). The potential difference \(V_A - V_B\), at the instant when current \(i = 2\) A and is increasing at a rate of 1 amp/second is:
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