Question:

A particle (A) is dropped from a height and another particle (B) is projected in horizontal direction with speed of 5 m/s from the same height then correct statement is :

Updated On: Apr 21, 2025
  • Particle (A) will reach at ground first with respect to particle (B)

  • Particle (B) will reach at ground first with respect to particle (A)

  • Both particles will reach at ground simultaneously

  • Both particles will reach at ground with same speed 

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The Correct Option is C

Solution and Explanation

The correct option is (C): Both particles will reach at ground simultaneously
For particle (A) 
h = \(\frac{1}{2}gt^2\)
tA\(\sqrt{\frac{2h}{g}}\) 

For particle (B) In the vertical direction 
Use s = ut + \(\frac{1}{2}at^2\)
\(\Rightarrow\) h = \(\frac{1}{2}gt_B^2\)
\(\Rightarrow\)\(t_B\) =\(\sqrt{\frac{2h}{g}}\)
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Concepts Used:

Motion in a straight line

The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion. 

Types of Linear Motion:

Linear motion is also known as the Rectilinear Motion which are of two types:

  1. Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
  2. Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.