Question:
A parallel beam of monochromatic light of
wavelength 5000 $\mathring{A}$ is incident normally on a
single narrow slit of width 0.001 mm. The light is
focussed by a convex lens on a screen placed in
focal plane. The first minimum will be formed for
the angle of diffraction equal to
A parallel beam of monochromatic light of
wavelength 5000 $\mathring{A}$ is incident normally on a
single narrow slit of width 0.001 mm. The light is
focussed by a convex lens on a screen placed in
focal plane. The first minimum will be formed for
the angle of diffraction equal to
Updated On: Jul 14, 2022
- 0$^{\circ}$
- 15$^{\circ}$
- 30$^{\circ}$
- 50$^{\circ}$
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The Correct Option is C
Solution and Explanation
: For first minimum, $ a sin \theta = n \lambda = I \lambda $
$sin \theta = \frac{\lambda}{a} = \frac{ 5000 \times {10}^{-10}}{0.001 \times {10}^{-3}} = 0.5 $
$\theta = 30 ^ \circ . $
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Concepts Used:
Single Slit Diffraction
In the single-slit diffraction experiment, we can examine the bending phenomenon of light or diffraction that causes light from a coherent source to hinder itself and produce an extraordinary pattern on the screen called the diffraction pattern.
Read More: Difference Between Diffraction and Interference
Central Maximum
