The question asks to identify the pair of isoelectric species having a bond order of one.
The correct answer is (C) \( O_2^{2-} \), \( F^- \), as these are isoelectronic species with a bond order of 1.
Isoelectronic species are those species that have the same number of electrons. The bond order can be calculated using the molecular orbital theory.
For O₂²⁻ and F₂, both are isoelectronic, and they both have a bond order of one, making them the correct pair for this question.
Match the LIST-I with LIST-II
LIST-I (Bonds) | LIST-II (Formations) |
---|---|
A. Ionic Bonds | Actual transfer of electrons from one atom to another atom |
B. Metallic Bonds | Partial sharing of valence electrons by the neighboring atoms |
C. Van der Waals Bonds | This type of bonding arises from dipolar interaction of crystals/molecules of the crystal. |
D. Hydrogen Bonds | This type of interaction between the oppositely charged ends of permanently polarized molecules. |
Choose the correct answer from the options given below: