Step 1: Let the number be \( N \). Given that \( N \mod 24 = 13 \), we can write: \[ N = 24k + 13 \quad \text{for some integer } k. \] Step 2: Now, divide \( N \) by 6: \[ N = 24k + 13 \quad \Rightarrow \quad (24k + 13) \mod 6. \] Since \( 24 \mod 6 = 0 \), this simplifies to: \[ 13 \mod 6 = 1. \] Conclusion: The remainder when the number is divided by 6 is \( 1 \).