Question:

A number is increased by 10% and then it is decreased by 10%, then the net decrease percentage is:

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When a number is first increased by a percentage and then decreased by the same percentage, the net change is always less than the original percentage increase or decrease.
Updated On: Mar 26, 2025
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The Correct Option is A

Solution and Explanation

Let the original number be \( N \). 
Step 1: After a 10\% increase, the new number becomes: \[ N' = N \times \left(1 + \frac{10}{100}\right) = N \times 1.10 \] 
Step 2: Now, after a 10\% decrease, the new number becomes: \[ N'' = N' \times \left(1 - \frac{10}{100}\right) = N \times 1.10 \times 0.90 = N \times 0.99 \] 
Step 3: The percentage decrease is: \[ \text{Percentage decrease} = \frac{N - N''}{N} \times 100 = \frac{N - 0.99N}{N} \times 100 = 1\% \] Thus, the net decrease percentage is 1%.

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