Let the original number be \( N \).
Step 1: After a 10\% increase, the new number becomes: \[ N' = N \times \left(1 + \frac{10}{100}\right) = N \times 1.10 \]
Step 2: Now, after a 10\% decrease, the new number becomes: \[ N'' = N' \times \left(1 - \frac{10}{100}\right) = N \times 1.10 \times 0.90 = N \times 0.99 \]
Step 3: The percentage decrease is: \[ \text{Percentage decrease} = \frac{N - N''}{N} \times 100 = \frac{N - 0.99N}{N} \times 100 = 1\% \] Thus, the net decrease percentage is 1%.