To determine the ratio of the radii of the two daughter nuclei, we use the formula for the nuclear radius: \( R = R_0 \cdot A^{1/3} \), where \( R_0 \) is a constant and \( A \) is the mass number.
Let the mass numbers of the daughter nuclei be \( A_1 = 125 \) and \( A_2 = 64 \).
The radius of the first nucleus \( R_1 \) is given by \( R_1 = R_0 \cdot 125^{1/3} \).
The radius of the second nucleus \( R_2 \) is given by \( R_2 = R_0 \cdot 64^{1/3} \).
We need the ratio \( \frac{R_1}{R_2} \), which is \(\frac{R_0 \cdot 125^{1/3}}{R_0 \cdot 64^{1/3}}\).
The \( R_0 \) terms cancel out, simplifying to \(\frac{125^{1/3}}{64^{1/3}}\).
This further simplifies to \(\left(\frac{125}{64}\right)^{1/3}\).
\( \frac{125}{64} = \frac{5^3}{4^3} \).
Thus, \(\left(\frac{5^3}{4^3}\right)^{1/3} = \frac{5}{4}\).
The ratio of the radii of the two daughter nuclei is \( 5:4 \).
Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A): The density of the copper ($^{64}Cu$) nucleus is greater than that of the carbon ($^{12}C$) nucleus.
Reason (R): The nucleus of mass number A has a radius proportional to $A^{1/3}$.
In the light of the above statements, choose the most appropriate answer from the options given below:
Match the LIST-I with LIST-II
| LIST-I (Type of decay in Radioactivity) | LIST-II (Reason for stability) | ||
|---|---|---|---|
| A. | Alpha decay | III. | Nucleus is mostly heavier than Pb (Z=82) |
| B. | Beta negative decay | IV. | Nucleus has too many neutrons relative to the number of protons |
| C. | Gamma decay | I. | Nucleus has excess energy in an excited state |
| D. | Positron Emission | II. | Nucleus has too many protons relative to the number of neutrons |
Choose the correct answer from the options given below:
The output (Y) of the given logic implementation is similar to the output of an/a …………. gate.
Nuclear physics is the field of physics that studies atomic nuclei and their constituents and interactions, in addition to the study of other forms of nuclear matter. Nuclear physics should not be confused with atomic physics, which studies the atom as a whole, including its electrons
‘R’ represents the radius of the nucleus. R = RoA1/3
Where,
The mass number (A), also known as the nucleon number, is the total number of neutrons and protons in a nucleus.
A = Z + N
Where, N is the neutron number, A is the mass number, Z is the proton number
Mass defect is the difference between the sum of masses of the nucleons (neutrons + protons) constituting a nucleus and the rest mass of the nucleus and is given as:
Δm = Zmp + (A - Z) mn - M
Where Z = atomic number, A = mass number, mp = mass of 1 proton, mn = mass of 1 neutron and M = mass of nucleus.