The force acting on a charged particle moving in a magnetic field is given by the Lorentz force equation: \[ \vec{F} = q (\vec{v} \times \vec{B}) \] Where:
- \( \vec{F} \) is the magnetic force,
- \( q \) is the charge of the particle,
- \( \vec{v} \) is the velocity vector of the particle,
- \( \vec{B} \) is the magnetic field vector.
For a negative charge, the direction of force is opposite to that predicted by the right-hand rule. Using the right-hand rule, point your fingers in the direction of the velocity vector (\(\vec{v}\), which is upward) and curl them in the direction of the magnetic field vector (\(\vec{B}\), which is towards the North).
Your thumb will point in the direction of the force on a positive charge.
Since the particle is negative, the force on the particle will be in the opposite direction to the thumb.
For this case, the force is directed towards the East.
Thus, the particle is deflected towards East.
The figure below shows an electrically conductive bar of square cross-section resting on a plane surface. The bar of mass of 1 kg has a depth of 0.5 m along the y direction. The coefficient of friction between the bar and the surface is 0.1. Assume the acceleration due to gravity to be 10 m/s\(^2\). The system faces a uniform flux density \( B = -1 \hat{z} \, \text{T} \). At time \( t = 0 \), a current of 10 A is switched onto the bar and is maintained. When the bar has moved by 1 m, its speed in metre per second is \(\underline{\hspace{2cm}}\) (rounded off to one decimal place).

200 ml of an aqueous solution contains 3.6 g of Glucose and 1.2 g of Urea maintained at a temperature equal to 27$^{\circ}$C. What is the Osmotic pressure of the solution in atmosphere units?
Given Data R = 0.082 L atm K$^{-1}$ mol$^{-1}$
Molecular Formula: Glucose = C$_6$H$_{12}$O$_6$, Urea = NH$_2$CONH$_2$