Question

\(A Na+BHO→ C NaOH + DH2,\) in this equation the values of \(A, B, C \) and \(D\) are 

• A. A=1, B=1, C=2, D=1
• B. A=2, B=2, C=2, D=1
• C. A=1, B=1, C=1, D=1
• D. A=2, B=1, C=2, D=1

Answer 1

The Correct Option is B

To solve the problem, we need to balance the chemical equation and find the values of A, B, C, and D in the equation:

1. Given Equation:
The unbalanced chemical equation is:
$ A \, \text{Na} + B \, \text{H}_2\text{O} \rightarrow C \, \text{NaOH} + D \, \text{H}_2 $

2. Balancing the Equation:
Let's balance the atoms on both sides of the equation:

Na: There is 1 Na on the left side (from Na) and 1 Na on the right side (from NaOH), so $ A = 1 $ and $ C = 1 $.
H: There are 2 H atoms from water (H2O) on the left side and 2 H atoms in NaOH and 2 H atoms in H2 on the right side. So, $ B = 1 $ and $ D = 1 $.
O: There is 1 O atom in NaOH on the right side, which balances the 1 O atom in H2O on the left side. Thus, $ B = 1 $ and $ C = 1 $.

3. Final Balanced Equation:
The balanced equation is:
$ 1 \, \text{Na} + 1 \, \text{H}_2\text{O} \rightarrow 1 \, \text{NaOH} + 1 \, \text{H}_2 $

Final Answer:
The values of A, B, C, and D are $ \mathbf{A = 1, B = 1, C = 1, D = 1} $.