1:3
4:9
1:2
5:9
Let, coffee comprises 16 units and cocoa comprises 9 units.
There are 25 units of coffee and 0 units of cocoa.
Let, x units of the mixture are removed and replaced with cocoa.
If x units of the mixture are removed then (25 - x) units of coffee left.
According to the question,
\((25-x)(1-\frac {x}{25}) = 16\)
\((25-x)\frac {(25-x)}{25} = 16\)
\((25-x)^2 = 25 \times 16\)
\((25-x)^2 = 400\)
\((25-x) = \sqrt {400}\)
\(25-x= 20\)
\(x = 5\)
Now, in mixture P, cocoa = 5 units
And, in mixture Q, cocoa = 9 units
The required ratio = 5:9
So, the correct option is (D): 5:9