A mixture of four peptides, PKKRK, RGERV, RYRGV and LVVYP, is loaded onto an ion-exchange column at pH = 7.2. If carboxymethyl (CM) cellulose is used as the stationary phase of this column, then which peptide elutes first?
Step 1: Nature of the stationary phase
Carboxymethyl (CM) cellulose is a cation-exchange resin.
- It contains negatively charged carboxyl groups at pH 7.2.
- Therefore, it binds to positively charged peptides (cationic residues).
- Neutral or negatively charged peptides will bind weakly or not at all, and thus elute first.
Step 2: Analyze the peptides at pH 7.2
We must consider the approximate charges of side chains at pH 7.2: - Lysine (K), Arginine (R): positively charged (+1 each).
- Glutamic acid (E): negatively charged (–1 each).
- Tyrosine (Y), Proline (P), Valine (V), Glycine (G), Leucine (L): neutral.
Step 3: Calculate net charges
PKKRK: Contains 3 Lys (+3), 1 Arg (+1), 1 Pro (0). Net charge $\approx +4$. Strongly cationic $⇒$ binds strongly to CM-cellulose.
RGERV: Contains Arg (+1), Glu (–1), Arg (+1), Val (0). Net charge $\approx +1$. Moderately positive $⇒$ binds moderately.
RYRGV: Contains Arg (+1), Tyr (0), Arg (+1), Gly (0), Val (0). Net charge $\approx +2$. Positive $⇒$ binds.
LVVYP: Contains Leu (0), Val (0), Val (0), Tyr (0), Pro (0). Net charge $\approx 0$. Neutral $⇒$ weak/no binding.
Step 4: Elution order
- Peptides with higher positive charge bind more strongly to the negatively charged CM-cellulose.
- Therefore, the order of elution will be from least positive to most positive.
- Neutral peptide LVVYP (charge 0) will elute first.
Therefore, the peptide that elutes first is (D) LVVYP.
Match the standard/stated cofactors in Column I with their respective enzymes in Column II
Match the immunological statements in Column I with the appropriate descriptions from Column II.
Match the syndromes listed in Column I with the cause/symptoms listed in Column II.
Match the hormones/precursors listed in Column I with their chemical type in Column II and the tissue of origin listed in Column III.
The \( F_{121} \) value of a known microorganism with \( Z \) value of \( 11^\circ C \) is 2.4 min for 99.9999% inactivation. For a 12D inactivation of the said microorganism at \( 143^\circ C \), the \( F \) value (in min) is .......... (rounded off to 3 decimal places)
Three villages P, Q, and R are located in such a way that the distance PQ = 13 km, QR = 14 km, and RP = 15 km, as shown in the figure. A straight road joins Q and R. It is proposed to connect P to this road QR by constructing another road. What is the minimum possible length (in km) of this connecting road?
Note: The figure shown is representative.
For the clock shown in the figure, if
O = O Q S Z P R T, and
X = X Z P W Y O Q,
then which one among the given options is most appropriate for P?