Question:

A mass m supported by a massless string wound around a uniform hollow cylinder of mass m and radius R. If the string does not slip on the cylinder, with what acceleration will the mass fall on release?

Updated On: May 1, 2024
  • 2g/3
  • g/2
  • 5g/6
  • g
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

For the mass m, $mg-T=ma$
As we know, $a=R \alpha$
So, $mg-T=mR\alpha$ .....(i)
Torque about centre of pully
$T x R = mR^2\alpha$ .....(ii)
From Eqs. (i) and (ii), we get, $a=g/2$
Hence, the acceleration with the mass of a body fall is g/2.
Was this answer helpful?
1
0

Top Questions on System of Particles & Rotational Motion

View More Questions