Question:

A mass $m$ moving horizontally (along the $x-axis)$ with velocity $v$ collides and sticks to a mass of $3m$ moving vertically upward (along the $y$ -axis) with velocity $2\,v$. The final velocity of the combination is

Updated On: Mar 14, 2024
  • $\frac{3}{4} v \widehat{i} + \frac{1}{4} v \widehat{j}$
  • $\frac{1}{4} v \widehat{i} + \frac{3}{2} v \widehat{j}$
  • $\frac{1}{3} v \widehat{i} + \frac{2}{3} v \widehat{j}$
  • $\frac{2}{3} v \widehat{i} + \frac{1}{3} v \widehat{j}$
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The Correct Option is B

Solution and Explanation

From the law of conservation of linear momentum
$mv \,\hat{ i }+(3 m )(2\, v ) \hat{ j } $
$=4 \,mv '$
$v'=\frac{v}{4} \hat{i}+\frac{3}{2} v\hat{j}$
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