Question:

A mass $m$ is attached to a thin wire and whirled in a vertical circle. The wire is most likely to break when:

Updated On: Nov 25, 2022
  • the mass is at the lowest point
  • inclined at an angle of $60^{\circ}$ from vertical
  • the mass is at the highest point
  • the wire is horizontal
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The Correct Option is A

Solution and Explanation

$T -mg = \frac{mu^{2}}{I} $
$ T =mg + \frac{mu^{2}}{I}$
The tension is maximum at the lowest position of mass, so the chance of breaking is maximum.
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