A mass is performing vertical circular motion (see figure). The average velocity of the particle is increased, then at which point the string will break :
- A
- B
- C
- D
The Correct Option is B
Solution and Explanation
it exerts the maximum outward pull when it is at the lowest point B.
Therefore, tension at B is maximum = Weight $+\frac{mv^2}{R}$
So, the string breaks at point B.
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