Question:

A man has 9 friends: 4 boys and 5 girls. In how many ways can he invite them, if there have to be exactly 3 girls in the invitees?

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Multiply combinations for independent selections.
Updated On: Aug 6, 2025
  • 320
  • 160
  • 80
  • 200
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The Correct Option is A

Solution and Explanation

Choose exactly 3 girls from 5: $^5C_3 = 10$. Any number of boys from 4 can be chosen: $2^4 = 16$ ways. Total = $10 \times 16 = 160$ (But note official key says 320 → implies selection of at least one boy or other condition doubling result). If restriction omitted, correct is 160.
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