Since there are 4 envelopes and each letter must go into one envelope, the total number of ways to arrange the letters into envelopes is the number of permutations of 4 letters. This is given by:
\(4!=244!\)
There is only 1 correct arrangement in which all the letters are in their correct envelopes.
The probability is the ratio of favorable outcomes to total possible outcomes:
\(\frac{1}{24}\)
The correct answer is (A) : 1/24
List-I | List-II (Adverbs) |
(A) P(exactly 2 heads) | (I) \(\frac{1}{4}\) |
(B) P(at least 1 head) | (II) \(1\) |
(C) P(at most 2 heads) | (III) \(\frac{3}{4}\) |
(D) P(exactly 1 head) | (IV) \(\frac{1}{2}\) |
LIST-I(EVENT) | LIST-II(PROBABILITY) |
(A) The sum of the number is greater than 11 | (i) 0 |
(B) The sum of the number is 4 or less | (ii) 1/15 |
(C) The sum of the number is 4 | (iii) 2/15 |
(D) The sum of the number is 4 | (iv) 3/15 |
Choose the correct answer from the option given below