Since there are 4 envelopes and each letter must go into one envelope, the total number of ways to arrange the letters into envelopes is the number of permutations of 4 letters. This is given by:
\(4!=244!\)
There is only 1 correct arrangement in which all the letters are in their correct envelopes.
The probability is the ratio of favorable outcomes to total possible outcomes:
\(\frac{1}{24}\)
The correct answer is (A) : 1/24
If the probability distribution is given by:
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(x) | 0 | k | 2k | 2k | 3k | k² | 2k² | 7k² + k |
Then find: \( P(3 < x \leq 6) \)
If \(S=\{1,2,....,50\}\), two numbers \(\alpha\) and \(\beta\) are selected at random find the probability that product is divisible by 3 :
