Question

A magnetic field of strength \( B = 2 \, \text{T} \) is applied perpendicular to a current-carrying conductor. If the current in the conductor is \( I = 3 \, \text{A} \) and the length of the conductor within the magnetic field is \( L = 1.5 \, \text{m} \), calculate the force acting on the conductor.

• A. \( 9 \, \text{N} \)
• B. \( 6 \, \text{N} \)
• C. \( 3 \, \text{N} \)
• D. \( 12 \, \text{N} \)

Hint:

The magnetic force on a current-carrying conductor is directly proportional to the magnetic field strength, the current, and the length of the conductor within the field. Use \( F = BIL \) to calculate it.

Answer 1

The Correct Option is B

The force on a current-carrying conductor in a magnetic field is given by the formula: \[ F = BIL \] Where: - \( F \) is the magnetic force, - \( B \) is the magnetic field strength, - \( I \) is the current, - \( L \) is the length of the conductor within the magnetic field. Substituting the given values: \[ F = 2 \times 3 \times 1.5 = 9 \, \text{N} \] Thus, the force acting on the conductor is \( 9 \, \text{N} \).