Question:

A machine component is processed at 5 workstations sequentially. The cycle time (in seconds) for each workstation is given. In mass production, the number of components produced per hour (steady state) is \(\underline{\hspace{2cm}}\). [in integer] \[ \begin{array}{|c|c|} \hline \text{Workstation} & \text{Cycle time (sec)} \\ \hline \text{WS-1} & 85 \\ \text{WS-2} & 55 \\ \text{WS-3} & 90 \\ \text{WS-4} & 65 \\ \text{WS-5} & 70 \\ \hline \end{array} \]

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In flow lines, system throughput is always limited by the slowest workstation.
Updated On: Jan 13, 2026
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Correct Answer: 40

Solution and Explanation

In a line of sequential workstations, the output rate is determined by the bottleneck (maximum cycle time). \[ t_{\max} = 90\ \text{seconds} \] Thus, production rate: \[ \text{units/hour} = \frac{3600}{90} = 40 \] Final answer: \[ \boxed{40} \]
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