Step 1: Understand the problem.
A loan of Rs. 6000 is to be paid back in three equal installments. The interest is compounded annually at a rate of 12.5%. We need to find the value of each installment to the nearest whole rupee.
Step 2: Use the formula for compound interest to calculate the value of each installment.
The formula for the compound interest on a loan with annual compounding is given by:
\( A = P \times (1 + \frac{r}{100})^t \)
where:
- \( A \) is the amount after \( t \) years,
- \( P \) is the principal,
- \( r \) is the rate of interest,
- \( t \) is the time in years.
In this case, the loan is Rs. 6000, and it will be repaid in three installments. Let the value of each installment be \( x \), and the installments are made at the end of each year.
The loan of Rs. 6000 will be divided into three equal payments. Each installment will accrue interest for a different amount of time:
- The first installment will accrue interest for 2 years.
- The second installment will accrue interest for 1 year.
- The third installment will not accrue any interest.
Let’s calculate the total amount that each installment contributes to the loan.
Step 3: Set up the equation for the total repayment.
The first installment grows for 2 years:
Amount after 2 years = \( x \times (1 + \frac{12.5}{100})^2 = x \times (1.125)^2 = x \times 1.265625 \)
The second installment grows for 1 year:
Amount after 1 year = \( x \times (1.125) = x \times 1.125 \)
The third installment does not grow as it is paid in the same year:
Amount = \( x \)
The total amount repaid is Rs. 6000, so the equation is:
\( x \times 1.265625 + x \times 1.125 + x = 6000 \)
Simplifying:
\( x \times (1.265625 + 1.125 + 1) = 6000 \)
\( x \times 3.390625 = 6000 \)
\( x = \frac{6000}{3.390625} \)
\( x \approx 1777.78 \)
The installment value is Rs. 1778 (rounded to the nearest whole rupee).
Final Answer:
The correct option is (D): Rs. 2915.