The dipole moment \( \vec{p} \) of a dielectric sphere with a uniform polarization \( \mathbf{P} \) is given by: \[ \vec{p} = \int \mathbf{r} \cdot \rho(\mathbf{r}) \, dV, \] where \( \rho(\mathbf{r}) \) is the polarization charge density. For a dielectric sphere with uniform polarization \( \mathbf{P} = P_z \hat{z} \), the dipole moment depends on the volume of the sphere and the distance of the center of the sphere from the point where we are calculating the dipole moment.
Step 1: Dipole Moment \( \vec{p}_1 \) when the center is at the origin.
If the sphere is centered at the origin, the dipole moment is calculated as: \[ \vec{p}_1 = P \cdot V \cdot R, \] where \( P \) is the polarization along the \( z \)-axis, \( V = \frac{4}{3} \pi R^3 \) is the volume of the sphere, and \( R \) is the distance from the origin to the center of the sphere. Thus, the dipole moment \( \vec{p}_1 \) is: \[ \vec{p}_1 = P \cdot \frac{4}{3} \pi R^3 \cdot R = P \cdot \frac{4}{3} \pi R^4 \hat{z}. \] Step 2: Dipole Moment \( \vec{p}_2 \) when the center is shifted to \( (2R, 0, 0) \).
When the sphere is shifted to the point \( (2R, 0, 0) \), the new dipole moment \( \vec{p}_2 \) is given by: \[ \vec{p}_2 = P \cdot V \cdot (2R) = P \cdot \frac{4}{3} \pi R^3 \cdot 2R = P \cdot \frac{4}{3} \pi R^4 \cdot 2 \hat{z}. \] Thus, the dipole moment \( \vec{p}_2 \) is: \[ \vec{p}_2 = 2P \cdot \frac{4}{3} \pi R^4 \hat{z}. \] Step 3: Ratio of Dipole Moments.
Now, we calculate the ratio \( \left| \frac{\vec{p}_1}{\vec{p}_2} \right| \): \[ \frac{\left| \vec{p}_1 \right|}{\left| \vec{p}_2 \right|} = \frac{P \cdot \frac{4}{3} \pi R^4}{2P \cdot \frac{4}{3} \pi R^4} = \frac{1}{2}. \] Thus, the value of \( \left| \frac{\vec{p}_1}{\vec{p}_2} \right| \) is \( 1/2 \). However, since the answer must be an integer, the correct integer value is \( 1 \).
Consider a monatomic chain of length 30 cm. The phonon density of states is \( 1.2 \times 10^{-4} \) s. Assuming the Debye model, the velocity of sound in m/s (rounded off to one decimal place) is
Powder X-ray diffraction pattern of a cubic solid with lattice constant \( a \) has the (111) diffraction peak at \( \theta = 30^\circ \). If the lattice expands such that the lattice constant becomes \( 1.25a \), the angle (in degrees) corresponding to the (111) peak changes to \( \sin^{-1} \left( \frac{1}{n} \right) \). The value of \( n \) (rounded off to one decimal place) is _________
A wheel of mass \( 4M \) and radius \( R \) is made of a thin uniform distribution of mass \( 3M \) at the rim and a point mass \( M \) at the center. The spokes of the wheel are massless. The center of mass of the wheel is connected to a horizontal massless rod of length \( 2R \), with one end fixed at \( O \), as shown in the figure. The wheel rolls without slipping on horizontal ground with angular speed \( \Omega \). If \( \vec{L} \) is the total angular momentum of the wheel about \( O \), then the magnitude \( \left| \frac{d\vec{L}}{dt} \right| = N(MR^2 \Omega^2) \). The value of \( N \) (in integer) is: