Using the basic proportionality theorem ($LM \parallel QR$):
\[\frac{PL}{PQ} = \frac{PM}{PR}\]
Substitute the known values:
\[\frac{5.7}{15.2} = \frac{PM}{5.7 + 5.5}\]
\[\frac{5.7}{15.2} = \frac{PM}{11.2}\]
Solve for $PM$:
\[PM = \frac{5.7 \times 11.2}{15.2} = 4.2 \, cm\]