Question:
A line is drawn through a fixed point $ P (\alpha,\beta) $ to cut the circle $ x^2 + y^2 = r^2$ at $A$ and $B,$ then $PA.PB$ is equal to
A line is drawn through a fixed point $ P (\alpha,\beta) $ to cut the circle $ x^2 + y^2 = r^2$ at $A$ and $B,$ then $PA.PB$ is equal to
Updated On: Jul 5, 2022
- $(\alpha+\beta)^2-r^2$
- $\alpha+\beta^2-r^2$
- $(\alpha+\beta)^2+r^2$
- none of these.
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The Correct Option is B
Solution and Explanation
Answer (b) $\alpha+\beta^2-r^2$
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