Question

A light body of momentum \( P_L \) and a heavy body of momentum \( P_H \), both have the same kinetic energy, then:

• A. \( P_L>P_H \)
• B. \( P_L<P_H \)
• C. \( P_L = P_H \)
• D. \( P_H = 2 P_L \)

Hint:

When two bodies have the same kinetic energy, the body with the larger mass will have a smaller momentum, since momentum is proportional to the square root of mass when kinetic energy is fixed.

Answer 1

The Correct Option is B

Given that both bodies have the same kinetic energy, we know that: \[ KE = \frac{P^2}{2m} \] Since the momentum of the two bodies is \( P_L \) and \( P_H \), and both have the same kinetic energy: \[ \frac{P_L^2}{2m_L} = \frac{P_H^2}{2m_H} \] The above equation implies that the body with the larger mass will have a smaller momentum because the kinetic energy is constant for both. Therefore, the light body must have less momentum than the heavy body. Thus, \( P_L<P_H \).