(a).(i) Carbon has an atomic number of 6 with an electronic configuration of 2, 4. This means:
• To form a C4+ cation, carbon would need to lose 4 electrons, requiring a large amount of energy to overcome the strong nuclear attraction.
• To form a C4− anion, carbon would need to gain 4 electrons, which would cause repulsion between the electrons in the small carbon atom.
Since both processes are energetically unfavorable, carbon forms covalent bonds by sharing electrons to achieve a stable configuration.
(ii) A homologous series is a group of organic compounds having the same general formula, similar chemical properties, and successive members differing by a \(CH_2\)group.
Example: Aldehydes.
- General formula: \(C_nH_{2n+1}CHO\)
- Two consecutive members:
1. Methanal (HCHO) 2. Ethanal (\(CH_3CHO\)).
(iii) Cyclohexane is a cyclic compound with the molecular formula \(C_6H_{12}\). Its structure is represented as follows:
(b)(i) A commercially important carbon compound with the -OH functional group is Ethanol (C2H5OH). It is widely used as a solvent, in alcoholic beverages, and as a fuel.
(ii) Sodium metal:
Ethanol reacts with sodium metal to produce sodium ethoxide and hydrogen gas.
\[\text{C}_2\text{H}_5\text{OH} + 2\text{Na} \rightarrow 2\text{C}_2\text{H}_5\text{ONa} + \text{H}_2.\]
Product: Sodium ethoxide and hydrogen gas.
Excess conc. sulphuric acid:
Ethanol reacts with excess concentrated sulphuric acid at 170°C to undergo dehydration, forming ethene and water.
\[\text{C}_2\text{H}_5\text{OH} \xrightarrow{\text{Conc. H}_2\text{SO}_4} \text{C}_2\text{H}_4 + \text{H}_2\text{O}.\]
Product: Ethene and water.
Ethanoic acid in the presence of an acid catalyst:
Ethanol reacts with ethanoic acid in the presence of an acid catalyst to form ethyl ethanoate (an ester) and water.
\[\text{C}_2\text{H}_5\text{OH} + \text{CH}_3\text{COOH} \xrightarrow{\text{H}^+} \text{CH}_3\text{COOC}_2\text{H}_5 + \text{H}_2\text{O}.\]
Product: Ethyl ethanoate and water.
Acidified potassium dichromate:
Ethanol is oxidized by acidified potassium dichromate to form ethanoic acid.
\[\text{C}_2\text{H}_5\text{OH} \xrightarrow{\text{K}_2\text{Cr}_2\text{O}_7/\text{H}^+} \text{CH}_3\text{COOH} + \text{H}_2\text{O}.\]
Product: Ethanoic acid.
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