A hyperbola has its centre at the origin, passes through the point $(4,2)$ and has transverse axis of length $4$ along the x-axis. Then the eccentricity of the hyperbola is :
- $\frac{2}{\sqrt{3}}$
- $\frac{3}{2}$
- $\sqrt{3}$
- $2$
The Correct Option is A
Solution and Explanation
$ 2a =4 a=2$
$ \frac{x^{2}}{4} - \frac{y^{2}}{b^{2}} = 1 $
Passes through $(4,2)$
$ 4 - \frac{4}{b^{2}} = 1 \Rightarrow b^{2} = \frac{4}{3} \Rightarrow e = \frac{2}{\sqrt{3}} $
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