Question

A Hydrocarbon which does not belong to the same homologous series of carbon compounds is:

• A. \( \text{C}_4\text{H}_{10} \)
• B. \( \text{C}_6\text{H}_{14} \)
• C. \( \text{C}_7\text{H}_{14} \)
• D. \( \text{C}_{10}\text{H}_{22} \)

Hint:

The general formula for alkanes is \( C_nH_{2n+2} \), for alkenes is \( C_nH_{2n} \), and for alkynes is \( C_nH_{2n-2} \).

Answer 1

The Correct Option is C

Hydrocarbons are classified into different homologous series such as alkanes, alkenes, and alkynes based on their molecular formula and functional groups.
- Alkanes follow the general formula \( C_nH_{2n+2} \), meaning they are saturated hydrocarbons.
- Alkenes have the formula \( C_nH_{2n} \) (unsaturated hydrocarbons with a double bond).
- Alkynes have the formula \( C_nH_{2n-2} \) (unsaturated hydrocarbons with a triple bond).
- \( \text{C}_4\text{H}_{10} \) (Butane) fits the formula for alkanes.
- \( \text{C}_6\text{H}_{14} \) (Hexane) fits the formula for alkanes.
- \( \text{C}_{10}\text{H}_{22} \) (Decane) fits the formula for alkanes.
- However, \( \text{C}_7\text{H}_{14} \) does not fit the alkane formula exactly, indicating it is either an alkene or alkyne, making it part of a different homologous series.
Thus, the correct answer is (C) \( \text{C}_7\text{H}_{14} \).