Inner radius (r1) of hemispherical tank = 1 m
Thickness of iron = 1cm = \(\frac{1}{100}\) m = 0.01 m
Outer radius of the tank, R = 1 m + 0.01m = 1.01m
Volume of the iron used to make the tank = \(\frac{2}{3}\pi\) R3 - \(\frac{2}{3}\pi\) r3
\(= \frac{2}{3}\pi\) (R3 - r3)
\(= \frac{2}{3} × \frac{22}{7} ×\) [(1.01m)3 - (1m)3]
\(= \frac{2}{3} × \frac{22}{7} ×\) [1.030301 m3 - 1 m3]
\(= \frac{2}{3} × \frac{22}{7}\) \(× \) 0.030301 m3
= 0.06348 m3 (approx.)
Therefore, 0.06348 m3 of iron is used to make the tank.
A driver of a car travelling at \(52\) \(km \;h^{–1}\) applies the brakes Shade the area on the graph that represents the distance travelled by the car during the period.
Which part of the graph represents uniform motion of the car?