To determine the heat absorbed along the path A → B → C, let's break down the solution step by step:
Given Data:
Using the first law of thermodynamics for path A → C:
\[ \Delta U = Q_{AC} - W_{AC} = 280 - 200 = 80\,\text{J} \]
Since internal energy is a state function, ΔU is the same for both paths A → C and A → B → C.
Now, for path A → B → C:
\[ \Delta U = Q_{ABC} - W_{ABC} \]
\[ 80 = Q_{ABC} - 80 \Rightarrow Q_{ABC} = 160\,\text{J} \]
Conclusion: The heat absorbed along the path A → B → C is 160 J.
The correct option is (C): 160 J
To understand the heat absorbed along path A → B → C in a thermodynamic process, we apply the First Law of Thermodynamics, which states:
ΔU = Q - W
Where:
Step 1: Apply the first law to path A → C
From the question, along path A → C:
Using the formula:
ΔU = Q - W = 300 - 200 = 100 J
This means that the internal energy increased by 100 J during the process. Since internal energy is a state function, this value of ΔU remains the same regardless of the path taken between states A and C.
Step 2: Apply the first law to path A → B → C
Now consider the alternate path A → B → C:
Rearranging the first law to solve for heat:
Q = ΔU + W = 100 + 60 = 160 J
Conclusion: The heat absorbed along the path A → B → C is 160 J. This is less than the heat absorbed along path A → C because less work is done in path A → B → C.
The correct option is (C): 160 J
The standard heat of formation, in kcal/mol, of $Ba^{2+}$ is:
Given: Standard heat of formation of SO₄²⁻(aq) = -216 kcal/mol, standard heat of crystallization of BaSO₄(s) = -4.5 kcal/mol, standard heat of formation of BaSO₄(s) = -349 kcal/mol.
A stream of superheated steam (2 MPa, 300°C) mixes with another stream of superheated steam (2 MPa, 400°C) through a steady-state adiabatic process. The flow rates of the streams are 3 kg/min and 2 kg/min, respectively. This mixture then expands in an adiabatic nozzle to a saturated mixture with quality of 0.77 and 1 kPa. Neglect the velocity at the nozzle entrance and the change in potential energies. The velocity at the nozzle exit (in m/s) is ......... (rounded off to two decimal places).
Use the following data:
At 2 MPa, 300 °C: Specific enthalpy of superheated steam = 3024.2 kJ/kg
At 2 MPa, 400 °C: Specific enthalpy of superheated steam = 3248.4 kJ/kg
At 1 kPa: Specific enthalpy of saturated water = 29.3 kJ/kg
At 1 kPa: Specific enthalpy of saturated vapour = 2513.7 kJ/kg
Thermodynamics in physics is a branch that deals with heat, work and temperature, and their relation to energy, radiation and physical properties of matter.
A thermodynamic system is a specific portion of matter with a definite boundary on which our attention is focused. The system boundary may be real or imaginary, fixed or deformable.
There are three types of systems:
A system undergoes a thermodynamic process when there is some energetic change within the system that is associated with changes in pressure, volume and internal energy.
There are four types of thermodynamic process that have their unique properties, and they are:
The Zeroth law of thermodynamics states that if two bodies are individually in equilibrium with a separate third body, then the first two bodies are also in thermal equilibrium with each other.
The First law of thermodynamics is a version of the law of conservation of energy, adapted for thermodynamic processes, distinguishing three kinds of transfer of energy, as heat, as thermodynamic work, and as energy associated with matter transfer, and relating them to a function of a body's state, called internal energy.
The Second law of thermodynamics is a physical law of thermodynamics about heat and loss in its conversion.
Third law of thermodynamics states, regarding the properties of closed systems in thermodynamic equilibrium: The entropy of a system approaches a constant value when its temperature approaches absolute zero.