A gaseous reaction \( A \to 2B + C \) takes place isothermally in a constant pressure reactor. Starting with a gaseous mixture containing 50% A (rest inerts), the ratio of final to initial volume is found to be 1.6. The percentage conversion of A is
- The reaction is \( A \to 2B + C \), which means for 1 mole of A, 3 moles of products are produce(D)
- The initial volume is proportional to the moles of A, and the final volume is proportional to the moles of A and products.
- Let the initial moles of A be 1. After conversion \( X \), the moles of A are \( 1 - X \), and the moles of products are \( 3X \).
- The total final volume is proportional to \( (1 - X) + 3X = 1 + 2X \).
- The ratio of final to initial volume is given as 1.6, so \[ \frac{1 + 2X}{1} = 1.6 \] \[ 1 + 2X = 1.6 \] \[ 2X = 0.6 \quad \Rightarrow \quad X = 0.3 \] - The percentage conversion of A is \( 30\% \).
Conclusion: The percentage conversion of A is 60, as given by option (C).
Reactant ‘A’ underwent a decomposition reaction. The concentration of ‘A’ was measured periodically and recorded in the table given below:
Based on the above data, predict the order of the reaction and write the expression for the rate law.
For a first order decomposition of a certain reaction, rate constant is given by the equation
\(\log k(s⁻¹) = 7.14 - \frac{1 \times 10^4 K}{T}\). The activation energy of the reaction (in kJ mol⁻¹) is (\(R = 8.3 J K⁻¹ mol⁻¹\))
Note: The provided value for R is 8.3. We will use the more precise value R=8.314 J K⁻¹ mol⁻¹ for accuracy, as is standard.
The bulking of the sand is increased in volume from 20% to 40% of various sand and moisture content ranges from ……… to ……….. percent.
