Question:

A gas at 350 K and 15 bar has molar volume 20 percent smaller than that for an ideal gas under the same conditions. The correct option about the gas and its compressibility factor (Z) is :

Updated On: June 02, 2025
  • Z< 1 and attractive forces are dominant
  • Z < 1 and repulsive forces are dominant
  • Z > 1 and attractive forces are dominant
  • Z > 1 and repulsive forces are dominant
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The Correct Option is A

Solution and Explanation

\(The \space correct  \space answer  \space is  \space A:Z<1  \space and  \space attractive  \space forces  \space are  \space dominant\)
\(\bullet\) Compressibility factor(Z) \(= \frac{V_{real}}{V_{ideal}}\)
\(\because \; V_{real} < V_{ideal} ;\) Hence Z < 1 
\(\bullet\) If Z < 1, attractive forces are dominant among gaseous molecules and liquefaction of gas will be easy.
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NEET Notification

Concepts Used:

States of Matter

The matter is made up of very tiny particles and these particles are so small that we cannot see them with naked eyes.

There are three States of Matter:

The three states of matter are as follows:

Solid State:

  • The solid-state is one of the fundamental states of matter.
  • Solids differ from liquids and gases by the characteristic of rigidity.
  • The molecules of solids are tightly packed because of strong intermolecular forces; they only oscillate about their mean positions.

Liquid State:

  • The molecules in a liquid are closely packed due to weak intermolecular forces.
  • These forces are weaker than solids but stronger than that of gases.
  • There is much space in between the molecules of liquids which makes their flowing ability easy.

Gaseous State:

  • In this state of matter, distances between the molecules are large (intermolecular distance is in the range of 10-7-10-5 cm.
  • The intermolecular forces experienced between them are negligible.
  • Thus, translatory, rotatory and vibratory motions are observed prominently in gases.