Question:

A force sensor has a sensitivity of 0.01 mV/N. If the sensor outputs a voltage of 2 mV, what is the corresponding force (in Newtons)?

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Sensor Sensitivity. Sensitivity = Output / Input. Therefore, Input = Output / Sensitivity. Ensure units are consistent (e.g., mV to V) before calculating.
Updated On: May 7, 2025
  • 100N
  • 150N
  • 200N
  • 250N
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The Correct Option is C

Solution and Explanation

Sensitivity (S) relates the output signal to the input measurand
Here, sensitivity relates output voltage (V) to input force (F)
$$ S = \frac{\text{Output Voltage}}{\text{Input Force}} = \frac{V}{F} $$ We are given: Sensitivity \(S = 0
01\) mV/N = \(0
01 \times 10^{-3}\) V/N
Output Voltage \(V = 2\) mV = \(2 \times 10^{-3}\) V
We need to find the force \(F\)
Rearranging the formula: $$ F = \frac{V}{S} $$ $$ F = \frac{2 \times 10^{-3} \, \text{V}}{0
01 \times 10^{-3} \, \text{V/N}} $$ $$ F = \frac{2}{0
01} \, \text{N} = \frac{200}{1} \, \text{N} = 200 \, \text{N} $$ The corresponding force is 200 N
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