Question:

A force $F$ acting on an object varies with distance $x$ as shown in the figure. The force is in $N$ and $x$ in $m$. The work done by the force in moving the obiect from $x=0$ to $x = 6 \,m$ is

Updated On: May 3, 2024
  • 18.0 J
  • 13.5 J
  • 9.0 J
  • 4.5 J
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The Correct Option is B

Solution and Explanation

Work done by force = Area under force displacement graph.
$=3 \times 3+\frac{1}{2} \times 3 \times 3=9+4.5=13.5 \,J$
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