Question:
A force\( F=20+10y \)acts on a particle in \(y-\)direction where \(F\) is in newton and y in meter. Work done by this force to move the particle from \(y=0\) to \( y=1\) m is:
A force\( F=20+10y \)acts on a particle in \(y-\)direction where \(F\) is in newton and y in meter. Work done by this force to move the particle from \(y=0\) to \( y=1\) m is:
Updated On: Apr 14, 2025
- \(30J\)
- \(5J\)
- \(25J\)
- \(20J\)
Hide Solution
Verified By Collegedunia
The Correct Option is C
Solution and Explanation
The correct option is (C) :\(25J\)
Was this answer helpful?
0
0
Top Questions on Work Power and Energy
- A machine with efficiency \( \frac{2}{3} \) used 12 J of energy in lifting a 2 kg block through a certain height and it is allowed to fall through the same. The velocity while it reaches the ground is:
- AP EAPCET - 2024
- Physics
- Work Power and Energy
- The average power generated by a 90 kg mountain climber who climbs a summit of height 600 m in 90 minutes is (Acceleration due to gravity \( g = 10 \) m/s\(^2\)):
- AP EAMCET - 2024
- Physics
- Work Power and Energy
The acceleration of a particle which moves along the positive \( x \)-axis varies with its position as shown in the figure. If the velocity of the particle is \( 0.8 \, \text{m/s} \) at \( x = 0 \), then its velocity at \( x = 1.4 \, \text{m} \) is:
- AP EAPCET - 2024
- Physics
- Work Power and Energy
- A particle of mass m moves on a straight line with its velocity increasing with distance according to the equation \( v = \alpha \sqrt{x} \), where \(\alpha\) is a constant. The total work done by all the forces applied on the particle during its displacement from \( x = 0 \) to \( x = d \), will be:
- JEE Main - 2024
- Physics
- Work Power and Energy
A force of \( (6x^2 - 4x + 3) \, \text{N} \) acts on a body of mass 0.75 kg and displaces it from \( x = 5 \, \text{m} \) to \( x = 2 \, \text{m} \). The work done by the force is
- AP EAMCET - 2024
- Physics
- Work Power and Energy
View More Questions
Questions Asked in NEET exam
- The magnetic moment of an iron bar is M. It is now bent in such a way that it forms an arc section of a circle subtending an angle of 60° at the centre. The magnetic moment of this arc section is
- NEET (UG) - 2024
- Magnetic moment
Identify the major product C formed in the following reaction sequence:
- NEET (UG) - 2024
- Chemical Reactions
- Given below are certain cations. Using inorganic qualitative analysis, arrange them in increasing group number from 0 to VI.
A) Al3+
B) Cu2+
C) Ba2+
D) Co2+
E) Mg2+
Choose the correct answer from the options given below- NEET (UG) - 2024
- Modern Periodic Law And The Present Form Of The Periodic Table
- The work done during reversible isothermal expansion of one mole of hydrogen gas at 25oC from a pressure of 20 atm to 10 atm is:
(Given R = 2.0 cal K-1 mol-1)- NEET (UG) - 2024
- Gas laws
- Consider the following reaction in a sealed vessel at equilibrium with concentrations of
N2 = 3.0 × 10–3 M, O2 = 4.2 × 10–3 M and NO = 2.8 × 10–3 M.
2NO(g)⇋N2(g) + O2(g)
If 0.1 mol L–1 of NO(g) is taken in a closed vessel, what will be degree of dissociation (a) of NO(g) at equilibrium?- NEET (UG) - 2024
- Equilibrium
View More Questions