Assuming steady, incompressible, inviscid flow in a horizontal pipe, we can apply Bernoulli's equation between two points along the pipe:
$$ P_1 + \frac{1}{2}\rho v_1^2 = P_2 + \frac{1}{2}\rho v_2^2 $$
(The \(\rho g h\) term is constant for a horizontal pipe and cancels out).
We also use the continuity equation for incompressible flow: \(A_1 v_1 = A_2 v_2\).
If the cross-sectional area decreases (\(A_2<A_1\)), the continuity equation implies that the velocity must increase (\(v_2>v_1\)).
According to Bernoulli's equation, if the velocity \(v\) increases, the term \(\frac{1}{2}\rho v^2\) (dynamic pressure) increases.
To keep the sum constant, the static pressure \(P\) must decrease.
Therefore, as the area decreases, velocity increases, and pressure decreases.