By the conservation of angular momentum about the center of the large disc:
\( L_i = L_f = 0 \)
Initially, the system is at rest, so the initial angular momentum is zero. When the motor is switched on, the clockwise angular momentum of the smaller disc is balanced by the counterclockwise angular momentum of the large disc.
The angular momentum of the smaller disc is:
\[ L_1 = I_1 \cdot \omega_1 = \frac{1}{2} M \left(\frac{R}{2}\right)^2 \cdot \omega = \frac{1}{8} MR^2 \cdot \omega \]
The angular momentum of the large disc is:
\[ L_2 = -MvR = -M(\omega_1 R)R = -MR^2 \cdot \omega_1 \]
Equating \( L_1 \) and \( L_2 \):
\[ \frac{1}{8} MR^2 \cdot \omega = MR^2 \cdot \omega_1 \]
Simplifying to find \( \omega_1 \):
\[ \omega_1 = \frac{\omega}{8} \]
Since the angular speed of the large disc is given by \( \omega/n \):
\[ \frac{\omega}{n} = \frac{\omega}{12} \]
Thus, the value of \( n \) is:
n = 12
n = 12