Question:

A disc has mass 'M' and radius 'R' . How much tangential force should be applied to the rim of the disc so as to rotate with angular velocity $'\omega '$ in time 't' ?

Updated On: May 8, 2024
  • $\frac{MR \omega}{4t}$
  • $\frac{MR \omega}{2t}$
  • $\frac{MR \omega}{t}$
  • $MR \omega t $
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The Correct Option is B

Solution and Explanation

Given, mass of disc $=M$
Radius of disc $=R$
We know that,
$\tau= I \alpha \,\,\,\,\,\,\, ...(i)$
But $\,\,\,\,\,\,\, \tau=F \times R$
$I=\frac{M R^{2}}{2}$
and $\,\,\,\, \alpha=\frac{\omega}{t}$
Therefore, $ F \times R =\frac{M R^{2}}{2} \times \frac{\omega}{t} $
$F =\frac{M R}{2} \times \frac{\omega}{t} \,\,\,\, F=\frac{M R \omega}{2 t} $
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Concepts Used:

System of Particles and Rotational Motion

  1. The system of particles refers to the extended body which is considered a rigid body most of the time for simple or easy understanding. A rigid body is a body with a perfectly definite and unchangeable shape.
  2. The distance between the pair of particles in such a body does not replace or alter. Rotational motion can be described as the motion of a rigid body originates in such a manner that all of its particles move in a circle about an axis with a common angular velocity.
  3. The few common examples of rotational motion are the motion of the blade of a windmill and periodic motion.