Question

A die is thrown once. What is the probability of getting a number greater than 4?

• A. \frac{1}{2}
• B. \frac{1}{3}
• C. \frac{1}{6}
• D. \frac{2}{3}

Hint:

Probability of an event = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}.

Answer 1

The Correct Option is B

A die has 6 faces numbered from 1 to 6.
Numbers greater than 4 are 5 and 6. So, favorable outcomes = 2.
Total possible outcomes = 6.
Probability = \frac{\text{Favorable outcomes}}{\text{Total outcomes}} = \frac{2}{6} = \frac{1}{3}.