Question

A die is thrown once. What is the probability of getting a number greater than 4?

• A. \(\frac{1}{2}\)
• B. \(\frac{1}{3}\)
• C. \(\frac{1}{6}\)
• D. \(\frac{2}{3}\)

Hint:

Probability of an event = \(\frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\).

Answer 1

The Correct Option is A

A die has 6 faces numbered from 1 to 6.
Numbers greater than 4 are 5 and 6. So, favorable outcomes \(= 2\).
Total possible outcomes \(= 6\).
Probability \(= \frac{\text{Favorable outcomes}}{\text{Total outcomes}} = \frac{2}{6} = \frac{1}{3}\).