Question:

A die is thrown 1000 times and the outcomes were recorded as follows:  
If the die is thrown once more, then the probability that it shows 5 is:

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To find the probability of an event, divide the number of favorable outcomes by the total number of possible outcomes.
Updated On: Mar 26, 2025
  • \(\frac{9}{50}\)
  • \(\frac{4}{25}\)
  • \(\frac{3}{20}\)
  • \(\frac{7}{25}\)
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The Correct Option is C

Solution and Explanation

Step 1: The probability of an event is given by the formula: \[ P(\text{event}) = \frac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}} \] Step 2: Here, the number of favorable outcomes is the frequency of 5, which is 150. The total number of outcomes is 1000. \[ P(\text{5}) = \frac{150}{1000} = \frac{3}{20} \] Thus, the probability that the die shows 5 is \(\frac{3}{20}\).
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