Question

A die has two faces each with number '1', three faces each with number '2' and one face with number '3'. If the die is rolled once, then \(P(1 \text{ or } 3)\) is:

• A. \( \frac{1}{2} \)
• B. \( \frac{1}{3} \)
• C. \( \frac{1}{6} \)
• D. \( \frac{2}{3} \)

Hint:

For "or" events in probability, simply add the individual probabilities of the events. Make sure not to double-count overlapping outcomes.

Answer 1

The Correct Option is A

We know that: \[ P(1) = \frac{2}{6}, \quad P(3) = \frac{1}{6} \] Now, for the event \( P(1 \text{ or } 3) \), we calculate: \[ P(1 \text{ or } 3) = P(1) + P(3) = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = \frac{1}{2} \] Thus, \( P(1 \text{ or } 3) = \frac{1}{2} \).